Monday, July 22, 2013

Subnetting Class C Address Problem 4


192.168.10.0 /28  (IP Address)


So  Subnet Mask is  255.255.255.240 (i.e. /27 )

224 means 4 ON bits and  4 OFF

Valid Subnets = 256-240 ==>16


Block :: 0 ,16, 32,48 , 64,80, 96,112, 128,144, 160,176,192,208,224,240 


Network = 2^4==> 16


host = 2^4-2==> 14



NETWORK 1




192.168.0.0 (Network ID)
192.168.0.1
192.168.0.2
192.168.0.3
192.168.0.4
.
.
.
.
192.168.0.11
192.168.0.12
192.168.0.13
192.168.0.14
192.168.0.15(Broadcast ID)

NETWORK 2


192.168.0.16 (Network ID)
192.168.0.17
192.168.0.18
192.168.0.19
192.168.0.20
.
.
.
.
.
192.168.0.27
192.168.0.28
192.168.0.29
192.168.0.30
192.168.0.31 (Broadcast ID)

NETWORK 3


192.168.0.32 (Network ID)
192.168.0.33
192.168.0.34
192.168.0.35
192.168.0.36
.
.
.
.
.
192.168.0.43
192.168.0.44
192.168.0.45
192.168.0.46
192.168.0.47 (Broadcast ID)


NETWORK 4


192.168.0.48 (Network ID)
192.168.0.49
192.168.0.50
192.168.0.51
192.168.0.52
.
.
.
.
.
192.168.0.59
192.168.0.60
192.168.0.61
192.168.0.62
192.168.0.63(Broadcast ID)




NETWORK 5




192.168.0.64 (Network ID)
192.168.0.65
192.168.0.66
192.168.0.67
192.168.0.68
.
.
.
.
192.168.0.75
192.168.0.76
192.168.0.77
192.168.0.78
192.168.0.79(Broadcast ID)

NETWORK 6


192.168.0.80 (Network ID)
192.168.0.81
192.168.0.82
192.168.0.83
192.168.0.84
.
.
.
.
.
192.168.0.91
192.168.0.92
192.168.0.93
192.168.0.94
192.168.0.95 (Broadcast ID)

NETWORK 7


192.168.0.96 (Network ID)
192.168.0.97
192.168.0.98
192.168.0.99
192.168.0.100
.
.
.
.
.
192.168.0.107
192.168.0.108
192.168.0.109
192.168.0.110
192.168.0.111(Broadcast ID)


NETWORK 8


192.168.0.112 (Network ID)
192.168.0.113
192.168.0.114
192.168.0.115
192.168.0.116
.
.
.
.
.
192.168.0.123
192.168.0.124
192.168.0.125
192.168.0.126
192.168.0.127 (Broadcast ID)


NETWORK  9




192.168.0.128 (Network ID)
192.168.0.129
192.168.0.130
192.168.0.131
192.168.0.132
.
.
.
.
192.168.0.139
192.168.0.140
192.168.0.141
192.168.0.142
192.168.0.143 (Broadcast ID)

NETWORK 10


192.168.0.144 (Network ID)
192.168.0.145
192.168.0.146
192.168.0.147
192.168.0.148
.
.
.
.
.
192.168.0.155
192.168.0.156
192.168.0.157
192.168.0.158
192.168.0.159 (Broadcast ID)

NETWORK 11


192.168.0.160 (Network ID)
192.168.0.161
192.168.0.162
192.168.0.163
192.168.0.164
.
.
.
.
.
192.168.0.171
192.168.0.172
192.168.0.173
192.168.0.174
192.168.0.175 (Broadcast ID)


NETWORK 12


192.168.0.176 (Network ID)
192.168.0.177
192.168.0.178
192.168.0.179
192.168.0.180
.
.
.
.
.
192.168.0.187
192.168.0.188
192.168.0.189
192.168.0.190
192.168.0.191 (Broadcast ID)


NETWORK 13



192.168.0.192 (Network ID)
192.168.0.193
192.168.0.194
192.168.0.195
192.168.0.196
.
.
.
.
192.168.0.203
192.168.0.204
192.168.0.205
192.168.0.206
192.168.0.207 (Broadcast ID)

NETWORK 14


192.168.0.208 (Network ID)
192.168.0.209
192.168.0.210
192.168.0.211
192.168.0.212
.
.
.
.
.
192.168.0.219
192.168.0.220
192.168.0.221
192.168.0.222
192.168.0.223 (Broadcast ID)


NETWORK 15


192.168.0.224 (Network ID)
192.168.0.225
192.168.0.226
192.168.0.227
192.168.0.228
.
.
.
.
.
192.168.0.235
192.168.0.236
192.168.0.237
192.168.0.238
192.168.0.239 (Broadcast ID)


NETWORK 16


192.168.0.240 (Network ID)
192.168.0.241
192.168.0.242
192.168.0.243
192.168.0.244
.
.
.
.
.
192.168.0.251
192.168.0.252
192.168.0.253
192.168.0.254
192.168.0.255 (Broadcast ID)

Sunday, July 21, 2013

Subnetting Class C Address Problem 3

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Problem 3.


192.168.10.0 /27  (IP Address)


So  Subnet Mask is  255.255.255.224 (i.e. /27 )

224 means 3 ON bits and  5 OFF

Valid Subnets = 256-224 ==>32


Block :: 0 , 32 , 64, 96, 128, 160, 192, 224 


Network = 2^3==> 


host = 2^5-2==> 30



NETWORK 1




192.168.0.0 (Network ID)
192.168.0.1
192.168.0.2
192.168.0.3
192.168.0.4
.
.
.
.
192.168.0.27
192.168.0.28
192.168.0.29
192.168.0.30
192.168.0.31 (Broadcast ID)

NETWORK 2


192.168.0.32 (Network ID)
192.168.0.33
192.168.0.34
192.168.0.35
192.168.0.36
.
.
.
.
.
192.168.0.59
192.168.0.60
192.168.0.61
192.168.0.62
192.168.0.63 (Broadcast ID)

NETWORK 3


192.168.0.64 (Network ID)
192.168.0.65
192.168.0.66
192.168.0.67
192.168.0.68
.
.
.
.
.
192.168.0.91
192.168.0.92
192.168.0.93
192.168.0.94
192.168.0.95 (Broadcast ID)


NETWORK 4


192.168.0.96 (Network ID)
192.168.0.97
192.168.0.98
192.168.0.99
192.168.0.100
.
.
.
.
.
192.168.0.123
192.168.0.124
192.168.0.125
192.168.0.126
192.168.0.127 (Broadcast ID)

x



NETWORK 5




192.168.0.128 (Network ID)
192.168.0.129
192.168.0.130
192.168.0.131
192.168.0.132
.
.
.
.
192.168.0.155
192.168.0.156
192.168.0.157
192.168.0.158
192.168.0.159 (Broadcast ID)

NETWORK 6


192.168.0.160 (Network ID)
192.168.0.161
192.168.0.162
192.168.0.163
192.168.0.164
.
.
.
.
.
192.168.0.187
192.168.0.188
192.168.0.189
192.168.0.190
192.168.0.191 (Broadcast ID)


NETWORK 7


192.168.0.192 (Network ID)
192.168.0.193
192.168.0.194
192.168.0.195
192.168.0.196
.
.
.
.
.
192.168.0.219
192.168.0.220
192.168.0.221
192.168.0.222
192.168.0.223 (Broadcast ID)


NETWORK 8


192.168.0.224 (Network ID)
192.168.0.225
192.168.0.226
192.168.0.227
192.168.0.228
.
.
.
.
.
192.168.0.251
192.168.0.252
192.168.0.253
192.168.0.254
192.168.0.255 (Broadcast ID)



Subnetting Class C Address Problem 2

Problem 2.


192.168.10.0 /26  (IP Address)


So  Subnet Mask is  255.255.255.192 (i.e. /26 )   ( 255 means 8 bits ON  and 192 means 2 bits ON ) 

(8+8+8+2 == 26)


192 means 2 ON bit and  6 OFF

Valid Subnets = 256-192 ==>64


Block :: 0 , 64 , 128, 192


Network = 2^2==>4 


host = 2^6-2==> 62



NETWORK 1




192.168.0.0 (Network ID)
192.168.0.1
192.168.0.2
192.168.0.3
192.168.0.4
.
.
.
.
192.168.0.59
192.168.0.60
192.168.0.61
192.168.0.62
192.168.0.63 (Broadcast ID)

NETWORK 2


192.168.0.64 (Network ID)
192.168.0.65
192.168.0.66
192.168.0.67
192.168.0.68
.
.
.
.
.
192.168.0.123
192.168.0.124
192.168.0.125
192.168.0.126
192.168.0.127 (Broadcast ID)

NETWORK 3


192.168.0.128 (Network ID)
192.168.0.129
192.168.0.130
192.168.0.131
192.168.0.132
.
.
.
.
.
192.168.0.187
192.168.0.188
192.168.0.189
192.168.0.190
192.168.0.191 (Broadcast ID)


NETWORK 4


192.168.0.192 (Network ID)
192.168.0.193
192.168.0.194
192.168.0.195
192.168.0.196
.
.
.
.
.
192.168.0.251
192.168.0.252
192.168.0.253
192.168.0.254
192.168.0.255 (Broadcast ID)


Friday, July 19, 2013

Subnetting Class C Address Problem 1

Problem 1.

192.168.10.0 /25  (IP Address)

So  Subnet Mask is  255.255.255.128 (i.e. /25 )

128 means 1 ON bit and  7 OFF
Host = 256-128 ==>128
Network = 2^X==>2^1 ==> 2


NETWORK 1




192.168.0.0 (Network ID)
192.168.0.1
192.168.0.2
192.168.0.3
192.168.0.4
.
.
.
.
192.168.0.123
192.168.0.124
192.168.0.125
192.168.0.126
192.168.0.127 (Broadcast ID)


NETWORK 2


192.168.0.128 (Network ID)
192.168.0.129
192.168.0.130
192.168.0.131
192.168.0.132
.
.
.
.
.
192.168.0.251
192.168.0.252
192.168.0.253
192.168.0.254
192.168.0.255 (Broadcast ID)


Thursday, July 18, 2013

CIDR Table


CLASSLESS INTER DOMAIN ROUTING(CIDR)


CIDR is the method that ISP(Internet Service Provider) use to allot the IP Address to companies or Home or College or Customer .They provide in a certain block size
when you recieve address from Internet service Provider that will get like this 192.168.10.32/28

For Example This will be telling  you what the subnet mask is?


128 |  1 0 0 0 0 0 0 0   (i.e. 1 Bit ON and 7 OFF)

192 |  1 1 0 0 0 0 0 0   (i.e. 2 Bits ON and 6 OFF)

224 |  1 1 1 0 0 0 0 0    (i.e. 3 Bits ON and 5 OFF)

240 |  1 1 1 1 0 0 0 0    (i.e. 4 Bits ON and 4 OFF)

248 |  1 1 1 1 1 0 0 0    (i.e. 5 Bits ON and 3 OFF)

252 |  1 1 1 1 1 1 0 0    (i.e. 6 Bits ON and 2 OFF)

254 |  1 1 1 1 1 1 1 0    (i.e. 7 Bits ON and 1 OFF)

255 |  1 1 1 1 1 1 1 1    (i.e. 8 Bits ON and  0 OFF)


Subnet Mask                                       CIDR Value

CLASS A

255.0.0.0                                                     /8
255.128.0.0                                                 /9
255.192.0.0                                                 /10
255.224.0.0                                                 /11
255.240.0.0                                                 /12
255.248.0.0                                                 /13
255.252.0.0                                                 /14
255.254.0.0                                                 /15

CLASS B

255.255.0.0                                                 /16
255.255.128.0                                             /17
255.255.192.0                                             /18
255.255.224.0                                             /19
255.255.240.0                                             /20
255.255.248.0                                             /21
255.255.252.0                                             /22
255.255.254.0                                             /23

CLASS C

255.255.255.0                                            /24
255.255.255.128                                        /25
255.255.255.192                                        /26
255.255.255.224                                        /27
255.255.255.240                                        /28
255.255.255.248                                        /29
255.255.255.252                                        /30
255.255.255.254                                        /31
255.255.255.255                                        /32



Wednesday, July 17, 2013

Subnet Mask working

subnet mask working:

Communication between a node on a local subnetwork and a node on a different subnetwork is like communication between nodes on two different networks. To a user, routing between subnetworks is transparent. Internally, however, the IP software recognizes any IP addresses that are destined for a subnetwork and sends those packets to the gateway for that subnetwork.
When subnet masks are used, an IP address is interpreted as follows:
[IP address] = [Network address][Subnetwork address][Host address]
This shows that when a network is divided into subnetworks, the host address portion of the IP address is divided into two parts, the subnetwork address and the host address.
For example, if a network has the Class B IP network address portion 129.47, the remainder of the IP address can be divided into subnetwork addresses and host addresses. This division is controlled by the network administrator to allow the most flexibility for network development at the site.
A subnet mask is the mechanism that defines how the host portion of the IP address is divided into subnetwork addresses and local host address portions. The subnet mask is a 32-bit, (four byte) number, just as an IP address is.

To understand the mechanics of the subnet mask, it is important to know a little of binary arithmetic.


CLASSLESS INTER DOMAIN ROUTING(CIDR)


CIDR is the method that ISP (Internet Service Provider) use to allot the IP Address to companies or Home or College or Customer .They provide in a certain block size
when you recieve address from Internet service Provider that will get like this 192.168.10.32/28
  
For Example This will be telling  you what the subnet mask is?


We will Discuss in Next Post this is the must Important Chapter for understanding  IP Address ?